What would be the diameter squared times 0.785 times height of a 4' diameter, 5' long cylindrical tank?

To determine the volume of the cylindrical tank using the formula you provided, it's important to first understand the components involved in the calculation. The formula is derived from the general volume formula for a cylinder, which is:

[ V = \pi \times (r^2) \times h ]

In this case, the diameter of the cylindrical tank is given as 4 feet. To find the radius, you divide the diameter by 2:

[ r = \frac{4 \text{ ft}}{2} = 2 \text{ ft} ]

Next, you square the radius:

[ r^2 = (2 \text{ ft})^2 = 4 \text{ ft}^2 ]

Now, the height of the tank is provided as 5 feet. Plugging the values into the volume formula, we can reformulate the calculation to fit the given expression of diameter squared times a constant (0.785) times the height:

Using the diameter directly:

[ \text{Diameter}^2 = (4 \text{ ft})^2 = 16 \text{ ft}^2 ]

Now, substituting this into the volume formula we use:

[

V = 0.